3(4m^2+2)+27=10m

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Solution for 3(4m^2+2)+27=10m equation: 



3(4m^2+2)+27=10m

We move all terms to the left:

3(4m^2+2)+27-(10m)=0

We add all the numbers together, and all the variables

-10m+3(4m^2+2)+27=0

We multiply parentheses

12m^2-10m+6+27=0

We add all the numbers together, and all the variables

12m^2-10m+33=0

a = 12; b = -10; c = +33;
Δ = b2-4ac
Δ = -102-4·12·33
Δ = -1484
Delta is less than zero, so there is no solution for the equation

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